For question 33, draw two upward paths away from a point (the carrier) with an angle of 60 degrees between them. Close the triangle at the top to indicate the distance between them at the desired point (1200mi). If both planes are traveling at the same speed, this makes an equilateral triangle. That means each plane has traveled 1200mi along its path. 1200mi/500mph = 12/5hr = 2 2/5hr, or answer A.
Question 46 is drawn deceptively. If segment AD is 5 units, and the area of 'rectangle' (drawn as a square) is 10, then segments AB and DC are 2 units each (Area = length x width). If point E is at the same 'height' as points A and B, then point E is 5 units 'high' - that is, above the DC baseline. The area of a triangle is 1/2 x base x height - with a base (DC) of 2 units and a height (E to baseline) of 5 units, we have 1/2 x 2 x 5 = 5, again answer A.
Hope this helps.
-T