Couldn't tell you for sure, but since I'm standing watch and bored out of my skull, here's a SWAG:
Say the aircraft ditched 100 yards off of the bow of the carrier (I dunno, but I suspect this number is generous).
The beam of the USS Nimitz is 134 feet, so figure the carrier's got to move laterally about 100 feet to avoid the misfortunate aircraft.
It's displacement is 97000 tons (which'll be something more than the mass of the ship, but I don't know by how much so I'll go with 97000 tons).
Also figure that the ship is moving about 30 knots (probably isn't, but this number will do for our purposes). At 30kt (180000ft per hour or 3000ft per minute), the ship will cover 100 yards in about 6 seconds, so you gotta move 97000 tons 100 feet laterally in less than 6 seconds. About here the math gets to complicated for me...
Any physics majors out there care to figure out how much force that would require, and is the rudder big enough to turn the carrier that fast when it's initial forward speed was 30kt?
Say the aircraft ditched 100 yards off of the bow of the carrier (I dunno, but I suspect this number is generous).
The beam of the USS Nimitz is 134 feet, so figure the carrier's got to move laterally about 100 feet to avoid the misfortunate aircraft.
It's displacement is 97000 tons (which'll be something more than the mass of the ship, but I don't know by how much so I'll go with 97000 tons).
Also figure that the ship is moving about 30 knots (probably isn't, but this number will do for our purposes). At 30kt (180000ft per hour or 3000ft per minute), the ship will cover 100 yards in about 6 seconds, so you gotta move 97000 tons 100 feet laterally in less than 6 seconds. About here the math gets to complicated for me...
Any physics majors out there care to figure out how much force that would require, and is the rudder big enough to turn the carrier that fast when it's initial forward speed was 30kt?